Optimal. Leaf size=175 \[ -\frac{a^{3/4} \tanh ^{-1}\left (\frac{\sqrt{\sqrt{a}-\sqrt{b}} \tanh (c+d x)}{\sqrt [4]{a}}\right )}{2 b^{3/2} d \sqrt{\sqrt{a}-\sqrt{b}}}+\frac{a^{3/4} \tanh ^{-1}\left (\frac{\sqrt{\sqrt{a}+\sqrt{b}} \tanh (c+d x)}{\sqrt [4]{a}}\right )}{2 b^{3/2} d \sqrt{\sqrt{a}+\sqrt{b}}}-\frac{1}{4 b d (1-\tanh (c+d x))}+\frac{1}{4 b d (\tanh (c+d x)+1)}+\frac{x}{2 b} \]
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Rubi [A] time = 0.258026, antiderivative size = 175, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.208, Rules used = {3217, 1287, 207, 1130, 208} \[ -\frac{a^{3/4} \tanh ^{-1}\left (\frac{\sqrt{\sqrt{a}-\sqrt{b}} \tanh (c+d x)}{\sqrt [4]{a}}\right )}{2 b^{3/2} d \sqrt{\sqrt{a}-\sqrt{b}}}+\frac{a^{3/4} \tanh ^{-1}\left (\frac{\sqrt{\sqrt{a}+\sqrt{b}} \tanh (c+d x)}{\sqrt [4]{a}}\right )}{2 b^{3/2} d \sqrt{\sqrt{a}+\sqrt{b}}}-\frac{1}{4 b d (1-\tanh (c+d x))}+\frac{1}{4 b d (\tanh (c+d x)+1)}+\frac{x}{2 b} \]
Antiderivative was successfully verified.
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Rule 3217
Rule 1287
Rule 207
Rule 1130
Rule 208
Rubi steps
\begin{align*} \int \frac{\sinh ^6(c+d x)}{a-b \sinh ^4(c+d x)} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{x^6}{\left (1-x^2\right )^2 \left (a-2 a x^2+(a-b) x^4\right )} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \left (-\frac{1}{4 b (-1+x)^2}-\frac{1}{4 b (1+x)^2}-\frac{1}{2 b \left (-1+x^2\right )}+\frac{a x^2}{b \left (a-2 a x^2+(a-b) x^4\right )}\right ) \, dx,x,\tanh (c+d x)\right )}{d}\\ &=-\frac{1}{4 b d (1-\tanh (c+d x))}+\frac{1}{4 b d (1+\tanh (c+d x))}-\frac{\operatorname{Subst}\left (\int \frac{1}{-1+x^2} \, dx,x,\tanh (c+d x)\right )}{2 b d}+\frac{a \operatorname{Subst}\left (\int \frac{x^2}{a-2 a x^2+(a-b) x^4} \, dx,x,\tanh (c+d x)\right )}{b d}\\ &=\frac{x}{2 b}-\frac{1}{4 b d (1-\tanh (c+d x))}+\frac{1}{4 b d (1+\tanh (c+d x))}+\frac{\left (a \left (\sqrt{a}+\sqrt{b}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-a-\sqrt{a} \sqrt{b}+(a-b) x^2} \, dx,x,\tanh (c+d x)\right )}{2 b^{3/2} d}+\frac{\left (a \left (1-\frac{\sqrt{a}}{\sqrt{b}}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-a+\sqrt{a} \sqrt{b}+(a-b) x^2} \, dx,x,\tanh (c+d x)\right )}{2 b d}\\ &=\frac{x}{2 b}-\frac{a^{3/4} \tanh ^{-1}\left (\frac{\sqrt{\sqrt{a}-\sqrt{b}} \tanh (c+d x)}{\sqrt [4]{a}}\right )}{2 \sqrt{\sqrt{a}-\sqrt{b}} b^{3/2} d}+\frac{a^{3/4} \tanh ^{-1}\left (\frac{\sqrt{\sqrt{a}+\sqrt{b}} \tanh (c+d x)}{\sqrt [4]{a}}\right )}{2 \sqrt{\sqrt{a}+\sqrt{b}} b^{3/2} d}-\frac{1}{4 b d (1-\tanh (c+d x))}+\frac{1}{4 b d (1+\tanh (c+d x))}\\ \end{align*}
Mathematica [A] time = 0.867199, size = 158, normalized size = 0.9 \[ \frac{\frac{2 a \tanh ^{-1}\left (\frac{\left (\sqrt{a}+\sqrt{b}\right ) \tanh (c+d x)}{\sqrt{\sqrt{a} \sqrt{b}+a}}\right )}{\sqrt{\sqrt{a} \sqrt{b}+a}}+\frac{2 a \tan ^{-1}\left (\frac{\left (\sqrt{a}-\sqrt{b}\right ) \tanh (c+d x)}{\sqrt{\sqrt{a} \sqrt{b}-a}}\right )}{\sqrt{\sqrt{a} \sqrt{b}-a}}+2 \sqrt{b} (c+d x)-\sqrt{b} \sinh (2 (c+d x))}{4 b^{3/2} d} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.051, size = 223, normalized size = 1.3 \begin{align*}{\frac{1}{2\,bd} \left ( \tanh \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-2}}-{\frac{1}{2\,bd} \left ( \tanh \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-1}}+{\frac{1}{2\,bd}\ln \left ( \tanh \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) }-{\frac{a}{bd}\sum _{{\it \_R}={\it RootOf} \left ( a{{\it \_Z}}^{8}-4\,a{{\it \_Z}}^{6}+ \left ( 6\,a-16\,b \right ){{\it \_Z}}^{4}-4\,a{{\it \_Z}}^{2}+a \right ) }{\frac{{{\it \_R}}^{4}-{{\it \_R}}^{2}}{{{\it \_R}}^{7}a-3\,{{\it \_R}}^{5}a+3\,{{\it \_R}}^{3}a-8\,{{\it \_R}}^{3}b-{\it \_R}\,a}\ln \left ( \tanh \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -{\it \_R} \right ) }}-{\frac{1}{2\,bd} \left ( \tanh \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-2}}-{\frac{1}{2\,bd} \left ( \tanh \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-1}}-{\frac{1}{2\,bd}\ln \left ( \tanh \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{{\left (4 \, d x e^{\left (2 \, d x + 2 \, c\right )} - e^{\left (4 \, d x + 4 \, c\right )} + 1\right )} e^{\left (-2 \, d x - 2 \, c\right )}}{8 \, b d} - \frac{1}{64} \, \int \frac{256 \,{\left (a e^{\left (6 \, d x + 6 \, c\right )} - 2 \, a e^{\left (4 \, d x + 4 \, c\right )} + a e^{\left (2 \, d x + 2 \, c\right )}\right )}}{b^{2} e^{\left (8 \, d x + 8 \, c\right )} - 4 \, b^{2} e^{\left (6 \, d x + 6 \, c\right )} - 4 \, b^{2} e^{\left (2 \, d x + 2 \, c\right )} + b^{2} - 2 \,{\left (8 \, a b e^{\left (4 \, c\right )} - 3 \, b^{2} e^{\left (4 \, c\right )}\right )} e^{\left (4 \, d x\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.39824, size = 3123, normalized size = 17.85 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.30782, size = 82, normalized size = 0.47 \begin{align*} -\frac{{\left (2 \, e^{\left (2 \, d x + 2 \, c\right )} - 1\right )} e^{\left (-2 \, d x - 2 \, c\right )}}{8 \, b d} + \frac{d x + c}{2 \, b d} - \frac{e^{\left (2 \, d x + 2 \, c\right )}}{8 \, b d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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